R there N E type of special loans to help single moms buy a home in WV?

Q. There are no decent homes to rent in my area and I just wish that I could get a place for me and my 2 children to live and call it home.

A. there has to be something here that would help...something in your life.

stay strong and stand your ground.



HELP FOR YOU
http://www.petitionspot.com/petitions/collectchildsupport

http://www.womenslaw.org/
http://www.nwlc.org/
http://www.womenslawproject.org/
http://www.nwwlc.org/
http://www.women-law.org/
http://www.hg.org/women.html
http://www.law.com/jsp/nj/specials.jsp?p=contact
http://law-library.rutgers.edu/ilg/njlaw.php
http://eligibility.sc.egov.usda.gov/eligibility/welcomeAction.do
http://www.hud.gov/offices/pih/programs/hcv/about/fact_sheet.cfm
http://www.hud.gov/offices/pih/programs/hcv/forms/index.cfm
http://www.hud.gov/offices/pih/pha/contacts/
http://www.singlemoms.org/info/main.htm
http://singlemothers.org/SMO/index.php
http://www.singlemotherresources.com/
http://www.angelfire.com/nj4/njcomputerchick
http://www.parentswithoutpartners.org/chapterfind.asp
http://www.mowaa.org/
http://modestneeds.org/
http://freecycle.org/
http://www.salvationarmyusa.org/usn/www_usn.nsf
http://www.redcross.org/where/chapts.asp
http://www.angeltree.org
http://www.secretsanta.org/
http://www.secretsanta.org/santacontent.aspx?ctype=13
http://www.coastside.org/id28.htm
http://www.christmaswish.org/
http://www.christmasorganizing.com/
http://www.toysfortots.org/donate/toys.asp


https://www.gavindebecker.com/resources.cfm


CA
http://www.icanaffordcollege.com/applications/homepage.cfm
HOME GRANTS
http://www.hud.gov/buying/index.cfm
http://www.hud.gov/offices/adm/grants/grantsrsrc.cfm
http://www.tdhca.state.tx.us/assist_homebuying.htm
http://www.hartprogram.com/staging/nuke/index.php
http://www.firsttimehome-buyer.org/
http://www.naeba.org/buying/government-grants-for-first-time-home-buyers.htm

YAHOO SUPPORT GROUP
http://groups.yahoo.com/group/SingleMomsOnaMission/

DEADBEATS
http://www.wantedposters.com/deadbeats_usa_a_to_f.htm
http://www.angelfire.com/creep/deadbeatparentssuck/
http://www.deadbeatjustice.com/list.htm
www.goodparentspay.com

CHILD SUPPORT CALCULATORS
http://www.divorcelawinfo.com/calculators.htm
http://www.alllaw.com/calculators/childsupport/
http://www.helpyourselfdivorce.com/child-support-calculators.html

LAWS
http://www.divorcelawinfo.com/states.htm
http://www.divorcehq.com/spprtgroups.html
http://www.divorceinfo.com/statebystate.htm
http://www.divorcenet.com/states
http://www.divorcesource.com/
http://www.divorcesource.com/info/deadbeat/deadbeat.shtml
http://www.divorcecentral.com/
http://family.findlaw.com/
http://family.findlaw.com/child-support/unpaid-support/support-orders-enforcement.html
http://www.divorcehq.com/deadbeat.html
http://www.divorceinfo.com/
http://www.divorceinanutshell.com/
http://www.lawchek.com/Library1/_books/domestic/qanda/childsupp.htm
http://family.findlaw.com/child-support/support-laws/state-child-/
http://www.supportguidelines.com/resources.html
http://www.supportguidelines.com/links.html
http://www.supportguidelines.com/laypersons.html
http://www.supportguidelines.com/articles/news.html
http://family.findlaw.com/child-support/support-basics/
http://www.spiesonline.net/deadbeat.shtml
http://www.childsupport-aces.org/index2.html

STATS
http://www.childsupport-aces.org/acesstatistics.html

FINDING DEADBEATS
http://www.wantedposters.com/skiptrace.htm
http://find.intelius.com/search-name.php?ReportType=1&
http://www.discreetdata.com/index.html
http://www.identitycrawler.net/people_search.html
http://www.efindoutthetruth.com/
http://www.peoplefinders.com
http://zabasearch.com/

FED AGENCIES
http://www.ncsea.org/
http://www.nfja.org/index.shtml
http://www.naag.org/issues/issue-consumer.php

REGIONAL FEDERAL CHILD SUPPORT OFFICES
http://www.acf.hhs.gov/programs/oro/regions/acf_regions.html

FACTS AND REGIONAL FEDERAL CS OFFICE INFO
http://www.acf.hhs.gov/programs/cse/fct/fct4.htm
http://www.divorcesource.com/WI/ARTICLES/beaulier11.html
http://www.acf.dhhs.gov/opa/fact_sheets/cse_factsheet.html
http://www.acf.dhhs.gov/programs/cse/newhire/index.html
http://www.acf.dhhs.gov/programs/cse/faq.html
http://www.acf.hhs.gov/programs/cse/newhire/fop/passport.htm
http://www.acf.hhs.gov/programs/cse/newhire/fop/fop.htm
http://www.acf.hhs.gov/programs/cse/newhire/faq/faq.htm
http://www.acf.dhhs.gov/programs/cse/extinf.html
http://www.acf.dhhs.gov/programs/cse/
http://www.acf.dhhs.gov/grants/grants_cse.html
http://www.acf.dhhs.gov/index.html
http://www.acf.hhs.gov/programs/region2/index.html
http://www.fms.treas.gov/faq/offsets_childsupport.html
http://www.govbenefits.gov/govbenefits_en.portal
http://www.fedstats.gov/qf/
http://www.fedworld.gov/gov-links.html
http://fatherhood.hhs.gov/pfs92/ch3.htm

SSI AND CHILD SUPPORT
http://www.ssa.gov/policy/docs/policybriefs/pb2004-02.html
http://www.ssa.gov/notices/supplemental-security-income/
http://family.findlaw.com/

FIND YOUR STATE REPS
http://www.usa.gov/
http://www.usa.gov/Agencies/State_and_Territories.shtml
http://www.nga.org
http://www.naag.org/attorneys_general.php

CHILD SUPPORT LIEN NETWORK
(some states work with them)
http://www.childsupportliens.com/

COLLECTORS
http://www.supportkids.com/
http://www.supportcollectors.com/faq.php
http://www.deadbeatdadfinders.com/
http://www.deadbeatdadfinders.com/links.html
http://www.childsupport-aces.org/index2.html
http://www.divorcesource.com/info/deadbeat/deadbeat.shtml

TAX INFO
http://www.taxsites.com/index.htm
http://www.divorceinfo.com/taxes.htm
http://www.irs.gov/taxtopics/tc354.html
http://www.irs.gov/taxtopics/tc422.html
http://www.irs.gov/faqs/faq4-5.html
http://www.irs.gov/localcontacts/index.html
http://www.irs.gov/advocate/index.html
http://www.irs.gov/publications/p525/index.html
http://www.fms.treas.gov/faq/offsets_childsupport.html
http://money.cnn.com/2007/02/14/pf/taxes/do_not_miss_tax_breaks/index.htm?postversion=2007021411

REPORT DEADBEATS
WORKING UNDER THE TABLE
(in writing, to your local and federal IRS offices)
http://www.irs.gov/localcontacts/index.html
http://www.irs.gov/compliance/enforcement/article/0,,id=106778,00.html

SEX OFFENDERS
http://www.mapsexoffenders.com/
http://www.scanusa.com/
http://www.nsopr.gov/
http://www.familywatchdog.us/Default.asp

Original Question

how to get a job?

Q. Hello just wondering how I would go about getting a job in a big store like tesco, adsa, toys r us etc...

Do i just go in the store and ask at the kiosk for an application form? fill it in and send it and go to an interview if they call me?

A. Absolutely....unless you want a Management Job, then you should jump through the proper hoops....service jobs are the easiest jobs to get today, as those are the only ones left out there.

Original Question

Toys R Us Orientation.?

Q. Not to sound rude, but please dont answer with a question or answer about general Orientations. I'm asking about Toys R Us ones, not anywhere else.

So, I was scheduled for a group interview last Thursday, but had a midterm and couldn't make it. For some reason, I got called in for Orientation for this Thursday. I'm guessing they liked my application or didn't really notice I wasn't there, but i've read how the interviews are on Glassdoor.
Anyhow, now I'm just confused what to wear. I'm not sure if they have out the shirts yet, but I heard they usually do it at orientation. Should I wear black slacks and a black polo? Should it be tucked in? They also asked for me to bring two forms of identification, I only have one, will my passport suffice?
From what i've read of other answers similar to my question, itll be almost like a work day after we watch a training video. If I get paid, how would it happen?

Please and thanks!
Btw, if you were an employee for toysrus before, that'd be really great help.

A. You need two forms of identification that would be like your passport and a drivers id or a library card or a student id or a birth certificate or a voter id card or any other thing with your name on it

Black pants and a white shirt tucked in. you will get paid by a check or it will be by direct deposit in a checing account if you have one.

Original Question

What makes complex numbers important?

Q. a + bi... My professor said something about CAT scans and e^x being related to sin(x) and cos(x) functions. He only touched upon this subject and then drifted back to integration techniques. Can someone briefly explain what imaginary and complex numbers are (Euler's formula derivation)? I'm only in calc II so please explain in layman's terms.
We haven't learned series (Taylor) yet. I should probably wait until I know how to do that before diving into this kind of math.

A. Beware: some parts here are definitely not for a layman but I guess you will understand them. In case not, you are welcome to ask for details. Here we go...


Complex numbers have one useful property that reals don't: every polynomial with complex coefficients is decomposable all the way to the root factors (x - root). This seemingly toy theorem has very significant corollaries and I would say that almost all applications of complex numbers is linked to it.


For example, it's known that complex numbers make a great aid in solving some important kinds of differential equations. The simplest case where they are needed, is:
a*y'' + b*y' + c*y = 0.

Theory then says we should look for special solutions in the form y = exp(λ*x). These are nice because they have simple derivatives:
y = exp(λx)
y' = λ exp(λx)
y'' = λ^2 exp(λx)
However, of course, only for some λ this is a solution. So, let's plug it in:
a*λ^2*exp(λx) + b*λ*exp(λx) + c*exp(λx) = 0
We can factor out the common term (which is surely nonzero):
a*λ^2 + b*λ + c = 0
So the derivatives of y became powers of λ.

Now this is a quadratic equation: you find some λ's using usual techniques and you immediately have some solutions of the original differential equation. So we know there are
* 2 solutions if b^2 - 4ac > 0
* 1 double root if b^2 - 4ac = 0 (this would be a bit more complicated, but let's not get in the details)
* no real solution if b^2 - 4ac < 0.

However, in the last case, we can use the quadratic formula unmodified if we allow complex numbers (and thus square roots of negative reals). So this gives also two roots λ, which are now imaginary (they have nonzero b in the form a + bi -- not to be confused with the coefficients a,b,c above!), and complex conjugate to each other (that is, they are a + bi and a - bi).

Here the Euler's formula comes into play, which tells that
exp(i*x) = cos(x) + i*sin(x).
[[N.B. exp(x) is the same as e^x.]]
The exponential function in complex numbers is obtained by a rather complicated process called analytical continuation. See below for details. However, it preserves all its nice properties except from that it was an injection. So, for example, the following multiplication rule holds:
exp(a + bi) = exp(a) exp(bi) = exp(a) * (cos(b) + i*sin(b))

So the two solutions of the DE can be written as
y1(x) = exp(λ1*x) = exp((a+bi)*x) = exp(ax) * (cos(bx) + i*sin(bx))
and
y2(x) = exp(λ2*x) = exp((a-bi)*x) = exp(ax) * (cos(-bx) + i*sin(-bx)) = exp(ax) * (cos(bx) - i*sin(bx))

The theory then says that if we have some set of solutions, any of their linear combinations is again a solution. So we can for example do
y3(x) = 1/2 * (y1(x) + y2(x)) = exp(ax) * cos(bx)
y4(x) = 1/(2i) * (y1(x) - y2(x)) = exp(ax) * sin(bx),
which returns us back to real functions of one real variable. Using this as a new so-called fundamental system, we can write a general solution of the DE as
exp(ax) * (A*cos(bx) + B*sin(bx)) with parameters A, B
or
C * exp(ax) * cos(bx + �0) with parameters C, �.

Therefore, we have solved a real equation with real unknown functions using complex numbers as an aid, and effectively exploiting their property that the polynomial ax^2 + bx + c can be solved regardless of the sign of its discriminant.

I hope this example clarifies your question a bit...


On Euler formula derivation:

The way I know for this uses so-called Taylor expansions of functions. To follow me, you have to believe that it holds that
exp(x) = sum [n = 0 to +�] x^n / n!
sin(x) = sum [n = 0 to +�] (-1)^n / (2*n+1)! * x^(2*n+1)
cos(x) = sum [n = 0 to +�] (-1)^n / (2*n)! * x^(2*n)
for each x in R.

We can take the first formula and simply say that we extend its validity to complex x's as well. Let's see then what that does if we plug i*x in the place of x:
exp(i*x) = sum [n = 0 to +�] (i*x)^n / n! = sum [n = 0 to +�] i^n * x^n / n!
So a term of i^n appeared now. That is:
* i^0 = 1
* i^1 = i
* i^2 = -1
* i^3 = -i
* i^4 = 1 again, so we can say:
** i^n = 1 for n = 0, 4, 8, 12, ...
** i^n = i for n = 1, 5, 9, ...
** i^n = -1 for n = 2, 6, 10, ...
** i^n = -i for n = 3, 7, 11, ...

We can handle the minuses easily but we will at least separate even n's from odd ones to split the real part (where i^n is a real number) and the imaginary part (where it is +i or -i). Therefore
* if n = 2*k, i^n * x^n / n! = (-1)^k * x^(2k) / (2k)!
* if n = 2*k+1, i^n * x^n / n! = (-1)^k * i * x^(2k+1) / (2k+1)!
If we let k go from 0 to +�, these two cases will reach each possible n. Finally,

exp(i*x) = sum [n = 0 to +�] (i*x)^n / n! = sum [n = 0 to +�] i^n * x^n / n! = sum [k = 0 to +�] (-1)^k * x^(2k) / (2k)! + i * sum [k = 0 to +�] (-1)^k * x^(2k+1) / (2k+1)!
which is nothing else than cos(x) + i*sin(x).

Original Question

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